If G1 and G2 receive an input of 50 uV, what would the output signal be?

In the context of polysomnography and the processing of physiological signals, the output signal of a differential amplifier is determined by the difference between the voltages applied to its two inputs (G1 and G2). If both G1 and G2 receive the same input of 50 µV, this means there is no voltage difference between them.

The output of a differential amplifier can be mathematically expressed as:

Output = G (V1 - V2)

Where:

• G is the gain of the amplifier (which can be set based on the specific application, but is not relevant when considering equal inputs).

• V1 is the voltage at G1.

• V2 is the voltage at G2.

In this case, since both inputs are equal (50 µV), the equation simplifies to:

Output = G (50 µV - 50 µV) = G (0 µV) = 0 µV

Thus, when the input signals are the same, the output will be 0 µV, which corresponds to no output signal being produced. This concept is crucial in understanding how differential amplifiers function in processing biological signals, ensuring that only the relevant differences between channels are represented in the final output.